2j^2-29j-15=0

Solution for 2j^2-29j-15=0 equation:

Simplifying
2j2 + -29j + -15 = 0

Reorder the terms:
-15 + -29j + 2j2 = 0

Solving
-15 + -29j + 2j2 = 0

Solving for variable 'j'.

Factor a trinomial.
(-1 + -2j)(15 + -1j) = 0

Subproblem 1
Set the factor '(-1 + -2j)' equal to zero and attempt to solve:

Simplifying
-1 + -2j = 0

Solving
-1 + -2j = 0

Move all terms containing j to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -2j = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -2j = 0 + 1
-2j = 0 + 1

Combine like terms: 0 + 1 = 1
-2j = 1

Divide each side by '-2'.
j = -0.5

Simplifying
j = -0.5
Subproblem 2
Set the factor '(15 + -1j)' equal to zero and attempt to solve:

Simplifying
15 + -1j = 0

Solving
15 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-15' to each side of the equation.
15 + -15 + -1j = 0 + -15

Combine like terms: 15 + -15 = 0
0 + -1j = 0 + -15
-1j = 0 + -15

Combine like terms: 0 + -15 = -15
-1j = -15

Divide each side by '-1'.
j = 15

Simplifying
j = 15
Solution
j = {-0.5, 15}